Question

An iron ring of 20 cm meandiameter having cross sectional area of 100 sqcm is wound with 400turns of wire.

Answer 1

Answer:

B = μ0 μr NI/l Wb/m2 ∴ 1 = 4π × 10− 7 × 1000 × 400 I/0.2π or I = 1.25 A Now, L = μ0 μr AN2/l = 4π × 10− 7 × 103 × (100 × 10− 4) × (400)2 /0.2π = 32.H E = 1/2(LI2) = 1/2 x 3.2 x 1.252 = 2.5JRead more on Sarthaks.com - https://www.sarthaks.com/492242/iron-ring-of-20-cm-mean-diameter-having-cross-section-of-100-cm-is-wound-with-400-turns-of-wire