Question

An iron ring of diameter 15 cm is uniformly wound with 450 turns of wire. A current of 2 A when passed through the coil establishes a flux density of 1.2 Wb/m square in the iron ring. Determine the value of relative permeability of iron.​

Answer 1

Answer:

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Explanation:

Solution:

n = N/2πr = 3000 / (2π x 0.15)

∴ B = μr μ0 n i = 1000 x 4π x 10-7 x (3000 / (2π x 0.15) x 2

∴ B = 1000 x 2 x 10-7 x (3000 /0.15) x 2 = 1000 x 2 x 10-7 x (20000) x 2

∴ B = 8 T

Ans: Magnetic field = 8 T