Question

an iron ring of mean circumference of 0.8 metre is uniformly found with 500 turns of wire when a current of 1A is passed through the coil, a flux density of 1.1T is produced in the iron. Find the permeability of the Iron under given conditions​

Answer 1

Permeability is defined as the ratio of the  magnetic induction( flux density) to the magnetic field.

Formula : μ = Β/Η  where μ = permeablitiy , B = magnetic flux density , H = magnetizing field.

H = N*I / L where N = number of turns , I = current , L = length

As the circumference is given it indicates the length

H = 500 × 1  / 0.8 = 625 A/T        (1)

μ = 625 / 1.1  ( from given and eqn (1))

μ = 568.181 H / m