An iron rod has a length of 50.0 cm at 12 degree Celsius at what temperature will its length becomes 50.12 cm coefficient of linear expansion of iron is equal to 12 Into 10 power minus 6 degree Celsius power minus 1
Answers
Answered by
33
L' = L + L@(T2-T1)
50.12 = 50 + 50×12×10^(-6)[T2-12]
REARRANGING:
6×10^(-4)[T2-12] = 0.12
T2 -12 = 200
T2 = 212
please make this answer brainliest .....
50.12 = 50 + 50×12×10^(-6)[T2-12]
REARRANGING:
6×10^(-4)[T2-12] = 0.12
T2 -12 = 200
T2 = 212
please make this answer brainliest .....
NNSS32311:
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mark this as brainliest
Answered by
9
L' = L + L@(T2-T1)
50.12 = 50 + 50×12×10^(-6)[T2-12]
REARRANGING:
6×10^(-4)[T2-12] = 0.12
T2 -12 = 200
T2 = 212
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