An iron rod has a length of 50.0 cm at 12 degree Celsius at what temperature will its length becomes 50.12 cm coefficient of linear expansion of iron is equal to 12 Into 10 power minus 6 degree Celsius power minus 1
Answers
Answered by
1
L' = L + L@(T2-T1)
50.12 = 50 + 50×12×10^(-6)[T2-12]
REARRANGING:
6×10^(-4)[T2-12] = 0.12
T2 -12 = 200
T2 = 212
Answered by
0
L' = L + L@(T2-T1)
50.12 = 50 + 50×12×10^(-6)[T2-12]
REARRANGING:
6×10^(-4)[T2-12] = 0.12
T2 -12 = 200
T2 = 212
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