Question

An iron rod has a length of 50.0 cm at 12 degree Celsius at what temperature will its length becomes 50.12 cm coefficient of linear expansion of iron is equal to 12 Into 10 power minus 6 degree Celsius power minus 1

Answer 1

L' = L + L@(T2-T1)

50.12 = 50 + 50×12×10^(-6)[T2-12]

REARRANGING:

6×10^(-4)[T2-12] = 0.12

T2 -12 = 200

T2 = 212

Answer 2

L' = L + L@(T2-T1)

50.12 = 50 + 50×12×10^(-6)[T2-12]

REARRANGING:

6×10^(-4)[T2-12] = 0.12

T2 -12 = 200

T2 = 212