Question

An iron rod has a length of 50.0 cm at 12 degree Celsius at what temperature will its length becomes 50.12 cm coefficient of linear expansion of iron is...

Answer 1

L' = L + L@(T2-T1)

50.12 = 50 + 50×12×10^(-6)[T2-12]

REARRANGING:

6×10^(-4)[T2-12] = 0.12

T2 -12 = 200

T2 = 212

Answer 2

L' = L + L@(T2-T1)

50.12 = 50 + 50×12×10^(-6)[T2-12]

REARRANGING:

6×10^(-4)[T2-12] = 0.12

T2 -12 = 200

T2 = 212