Question

an iron rod has a length of 50 m when the temperature is 20 degrees Celsius by how much will it expand when temperature rises to 30 degrees 30 degrees Celsius take linear expansivity is equal to 0.00001 to pack Kelvin what is the solution how can I solve it mathematically​

Answer 1

Answer:

=L1△T△L(1)L1=50cmL2=50.06cm△L=0.06cmT1=20℃T2=95℃△T=75℃

Putting value in (1) to find coefficient of Linear expansion

α=(50)(75)0.06α=16×10−6℃−1

Now, temperature at 0oC

Length at 0oC=L3

L3=L2(1+α△T)△T=0−20℃△T=−20℃L3=50[1+16×10−6×(−20)]L3=49.984cm