Math, asked by smithalatheesh56, 1 month ago

An iron rod is bend to make a circle with diameter 4 cm, what will be the diameter of the circle
made by an iron rod of length half of the first?​

Answers

Answered by Naolin
0

Answer:

2

Step-by-step explanation:

For first the rod may be of any size and when formed circle it is 4cm

Then in the second case if the size of the rod is halved, then the Diameter will also be halved

Hence 4 ÷ 2 = 2

Answered by tonystarky247
0

Step-by-step explanation:

Let length of iron rod = x

Perimeter of circle = Length of iron rod = x

2πr = x

2r = x/π

d = x/π

Let the length is half now = x/2

2πr' = x/2

2r'= x/2π

d' = x/2π

d' = d/2

So,, diameter of circle will be reduced by half also.

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