Question

An iron rod is subjected to a magnetic field of 1200A/M.The magnetic susceptibility of iron is 599. calculate its permeability and the magnetic flux per area produced.

Answer 1

Explanation:

Given: Magnetizing field = H = 1200 A/m, susceptibility = χ = 599, μo = 4π x 10-7 Wb/Am.

To Find: permeability = μ = ?, Magnetic flux per unit area = B = ?

Solution:

μ = μo ( 1 + χ)

∴ μ = 4π x 10-7 ( 1 + 599) = 4 x 3.142 x 10-7 x 600 = 7.536 x 10-4 H/m.

Now μ = B/H

∴ B = μ H = 7.536 x 10-4 x 1200 = 0.904 T

Ans: Permeability is 7.536 x 10-4 H/m and magnetic flux per unit area = 0.904 T

Thanku.