Question

an iron rod of length 50m and at a temperature of 60°c is heated to 70°c . calculate it new length [linear expansivity of iron =1.2×10^ -5

Answer 1

Answer: 50.0060 m

Explanation:

Given

Li= 50m

Δθ=(70-60) degree C

α= 1.2*10^-5 /degree C

We know that:

Lf=Li(1+αΔθ)

=50(1+(1.2*10^-5*10))

=50*(1+0.00012)

=50*1.00012

=50.0060 m