An iron rod of mass 50kg and length 2m is hung horizontally by two vertical strings, 10 cm from both ends of the rod .
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12
Answer:
Length= 2b m
Height= h= 4m
1) area of the four walls of the room = 2(length+breadth)*h
2(2b+b)*4=120m^2
8*3b=120
b=120/(8*3)
b=5m
Therefore
Breadth=b=5m
Length=2b=2*5=10m
2)area of the floor= length*breadth
=10m*5m
=50m^2
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1
Step-by-step explanation:
uper answer is right..........
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