Question

An iron rod of susceptibility 599 is subjected to a
magnetising field of 1200 A m-1. The
permeability of the material of the rod is :
(Ho= 4m x10-7Tm A-1)
(1) 2.4 x 10-5 Tm A-1
(2) 2.4mx 10-7 T mA-1
(3) 2.4TX 10-4 T mA-1
(4) 8.0x10-5 T m A-1​

Answer 1

Explanation:

3) 2.4 π × 10–4 T m A–1 mr = xm + 1 = 599 + 1 = 600 m = mo mr = 4 π × 10–7 × 600

Answer 2

12th/Physics

Magnetism and Matter

Answer :

Magnetic susceptibility of rod = 599

Field intensity = 1200 A/m

We have to find the permeability of the material of the rod$.$

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◈ Relation between magnetic susceptibility of matter and relative permeability is given by

$\dag\:\underline{\boxed{\bf{\pink{\mu_r=1+\chi_m}}}}$

• $\sf{\mu_r}$ denotes relative permeability
• $\sf{\chi_m}$ denotes magnetic susceptibility

$:\implies\sf\:\mu_r=1+\chi_m$

$:\implies\sf\:\mu_r=1+599$

$:\implies\bf\:\mu_r=600$

◈ Relative permeability of medium is defined as the ratio of permeability of medium to the permiability of free space.

$\leadsto\sf\:\mu_r=\dfrac{\mu}{\mu_o}$

$\leadsto\sf\:\mu=\mu_r\times \mu_o$

$\leadsto\sf\:\mu=600\times (4\pi\times 10^{-7})$

$\leadsto\sf\:\mu=2400\pi\times 10^{-7}$

$\leadsto\:\boxed{\bf{\purple{\mu=2.4\pi\times 10^{-4}\:TmA^{-1}}}}$