Question

an iron sphere of density 8g/cc weights 20g in air. calculate its weight in water.​

Answer 1

Answer:

I don't know but I will try

Db=8g/cc

d=20g

db/dl=w1/w1-w2

Answer 2

Answer:

The iron sphere will weigh 17.5g in water.

Step-by-step explanation:

The sphere weighs 20g in air.

Since its a solid iron sphere, it will completely submerge into the water.

Now according to the Archimedes' principle a body immersed in water will be subjected to an upwards force equal to the weight of the displaced water. This will result in apparent weight loss of the iron sphere.

Since the sphere is completely submerged it will displace the volume of water equal to its own volume = mass / density.

                                                  = ( 20 / 8 ) cc = 2.5 cc.

Mass of this displaced water = 2.5 × 1 g    [ density of water taken 1 g/cc ]

So during submerged in water the iron sphere will weigh

= actual weight in air - weight of displaced water

= 20 - 2.5 g

= 17.5 g

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