Question

an iron sphere of mass 100kg is suspended freely from a rigid support by means of a rope of length 2m the horizontal force required to displace it horizontally through 50cm is

Answer 1

The Sine of the angle made by the rope with the rigid support after the horizontal displacement is given by 50/200 . Hence .the angle is arcsin( 50/200) ,which is arcsin(0.25) , 14.4 degrees. By use of components for mg, T equals mg cos Theta ,giving T. The horizontal force necessary to displace the body is the same as the net force in horizontal direction ,which is Mg sin Theta .  so the calculated answer is 250N.