An iron sphere of mass 1kg is dropped from beight of 10m. If the acceleration of sphere is 9.8m/s2. calculate the momentum transferred to the ground by all.
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v2=0×0+2×9.8×10
v2=0+196
v2=196
v=14
momentum (P)=mv(mass×velocity)
P=1×14
therefore momentum is equal to 14
v2=0+196
v2=196
v=14
momentum (P)=mv(mass×velocity)
P=1×14
therefore momentum is equal to 14
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