Question

An iron sphere of mass 4 kg is dropped from a height of 10 m. If the acceleration of the sphere is 9.8 ms², calculate the momentum transferred to the ground by the ball.​

Answer 1

Hi friend,

We know that

S=ut +1/2 at²

Since initial velocity is 0,

S= 1/2 at²

T² = 2S/a

T²= 2×10/9.8

T = 1.428 secs.

Velocity = acceleration × time

Velocity = 9.8 ×1.428

Velocity = 14 m/s.

Momentum (p) = mv

P=1×14

P=14 kg m/s.

Hope this helped you a little!!!

mark brainlest