An Iron sphere of radius 'a' unit is immersed completely in water contained In a right circular cone of semi vertical angle 30, water is drained off from the cone
til its surface touches the sphere. Find the volume of water remaining in the cone.
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Answer:
5πa³/3
Step-by-step explanation:
Let R and H be the radius and height of the cone .
In ΔBOC
tan 30° = BC/AC
1/√3 = R / H
H =R √3
In ΔOPD
sin 30° = PD/ OP
1/2 = a/H-a
H -a = 2a
H = 3a
Put H value
√3 R = 3a
H = 3a
R = √3 a
Volume of Cone = 1/3 π R² H = 3πa³
Volume of sphere = 4/3 πa³
Volume of water remaining in the cone = 3πa³-4/3 πa³
= 5/3πa³
To keep
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