an iron spherical ball has been melted and recast into smaller balls of equal size. if radius of each of the smaller balls 1 by 4 of the radius of the original ball, how many such balls are made? Compare the surface area, of all the smaller balls combined together with that of the original ball .
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Answer:
64 balls
Step-by-step explanation:
Let the radius of bigger ball =R
Let the radius of smaller ball =r
Let the number of balls recasted=x
Then: R×¼ = r (According to the question)
Volume of sphere=4/3×π×(radius)³
Therefore.
Volume od bigger ball= x(Volume of small ball)
i.e
4/3×π×R³=x(4/3×π×r³)
substitute R=4r, we get,
(4r)³=x(r³)
Hence,
x=64.
Hope this is helpful..
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