an iron spherical ball of volume 232848cmcube has been melted and converted into a cone with vertical angel of 120 degree then height of the cone is
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hello , here...is Ur answer dear.
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Sol.
let the radius of the base be r and height be h.
since vertical angle is 120°, tan (120/2)=r/h
so r —sqrt(3)*h. since the same amount of metal is used, the volume of the cone would be 232848 cubic metre.
pi *r *r *h/3= 232848 and h -sprt(3)*r
pi *r^3= 232848* sqrt(3)
r = 50.45 metres.
h = 87.374
<<<☺>>>
<<☺>>
HOPE it's helps you.
Sol.
let the radius of the base be r and height be h.
since vertical angle is 120°, tan (120/2)=r/h
so r —sqrt(3)*h. since the same amount of metal is used, the volume of the cone would be 232848 cubic metre.
pi *r *r *h/3= 232848 and h -sprt(3)*r
pi *r^3= 232848* sqrt(3)
r = 50.45 metres.
h = 87.374
<<<☺>>>
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