Question

an irregular object with a mass of 18 kg displace 2.5 L of water when placed in a large overflow container . calculate the density of the object In g/ml

Answer 1

Mass of an irregular object = 18 kg = 18 × 1000 = 18000 grams

Volume of water displaced = 2.5 L

Since, the volume of the water displaced will be equal to the volume of the irregular object.

Hence, the volume of irregular object = 2.5 L = 2. 5 × 1000 ml = 2500 ml

Density of an irregular object = $\frac{mass}{volume}$

Density = $\frac{18000}{2500}$

Density = $7.2 \frac{g}{ml}$

Hence, the density of irregular object is $7.2 \frac{g}{ml}$.