Question

An irregular object with a mass of 18kg displaces 2,500 mL of water when placed in a large overflow container caculate the density

Answer 1

Mass of an irregular object = Mass of an irregular object = 18 kg = 18 × 1000 = 18000 grams

Volume of water displaced = 2.5 L

Since, the volume of the water displaced will be equal to the volume of the irregular object.

Hence, the volume of irregular object is

2.5 L = 2. 5 × 1000 ml = 2500 ml

Density of an irregular object = mass/volume

Density = 18000/2500

Density = 7.2 g/ml

Hence, the density of irregular object is 7.2 g/ml.

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