Question

An irregular pentagon has four interior angles of 60°, 80°, 100° and 125°. What is the size of the fifth interior angle?

Answer 1

Answer:

175°

Step-by-step explanation:

A pentagon always add up to 540 degrees so;

Let n be the fifth interior angle

60°+ 80°+100° +125°+n= 540°

365°+n                          =540°

365°-365° +n                =540°-365°

n                                    =175°

So the fifth interior angle will be 175°

Hope my answer helps