An irregular shaped piece of gold was lowered into a graduated cylinder holding a volume of water equal to 17 mL. The height of the water Rose to 20 mL.If the mass of the gold was 27 g,what was its density
Answers
Given : An irregular shaped piece of gold was lowered into a graduated cylinder holding a volume of water equal to 17 mL
The height of the water Rose to 20 mL
the mass of the gold was 27 g,
To Find : what was its density
Solution:
1 ml = 1 cm³
volume of water equal to 17 mL
The height of the water Rose to 20 mL
=> Volume of gold = 20 - 17 = 3 mL or 3 cm³
the chain weighs 27g and it displaces 3 cm³ of water
=> Specific density of chain = chain weight / Volume of water displaced
=> Specific density of chain = 27/ 3
=> Specific density of chain = 9
Specific density of gold = 9
density of gold = 9 g/cm³
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