An irrigation channel is carrying 2.0 cumec/s to the culturable command area of 1500ha with an intensity of irrigation of 50%. If the base period of crop is 140 days the duty of channel in ha/cumec/s is?
Answers
Answer:
(A) For Crop A:
Area under irrigation =1200 x 0.4 = 480 hectares
Kor period = b= 20 days
Kor depth = D= 10 cm= 0.1 m
Duty = ∆= 8.64 b/D = (8.64 x 20/0.1) =1728 hectares/cumec
Hence discharge required = Area under irrigation/ outlet factor=480/1728 = 0.278 cumec
(B) For Crop B:
Area under irrigation =1200 x 0.35 = 420 hectares
Kor period = b= 15 days
Kor depth = D= 16 cm= 0.16 m
Duty = ∆= 8.64 b/D = (8.64 x 15/0.16) =810 hectares/cumec
Hence discharge required = Area under irrigation/ outlet factor=420/810 = 0.519 cumec
Thus, the design discharge of water course= 0.276 +0.519= 0.8 cumec
Answer:
375 hectares/cumec
Explanation:
Total area under crop = 50/100 x 1500 =750 hectares
Discharge of canal = Area /Duty =A/ D
2 = 750/D
D = 750/2 = 375 hectares/cumec