an is an object is placed in front of concave mirror the the height of the images for 4 CM. And the height of the images formed 8cm what is the magnification
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Answered by
1
ANSWER
Given, h
o
=4cm,u=+30cm,f=+20cm
To find: v,h
i
and nature of image
From mirror formula, we have
u
1
+
v
1
=
f
1
∴
v
1
=
f
1
−
u
1
=
uf
u−f
v=
uf
u−f
=
30cm−(20cm)
30cm×20cm
=
+10
600cm
=+60cm
Magnification, m=
h
o
h
i
=−
u
v
or h
i
=−
u
v
×h
o
=−(−
+30fm
+60cm
)×4cm=−8cm
Thus, image is formed at a distance of 60cm in front of the mirror. Height of the image is 8cm. As v is positive, the image is real. Since h
i
is negative, it is inverted.
Answered by
2
Answer:
continuation of attachment
Thus image is formed 60 cm in front of a concave mirror .Height of image is +8cm.
As V is positive and image is real and height of image is -ve.It is inverted
Explanation:
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