Math, asked by raazsingh47, 1 year ago

An iscoscles triangle has perimeter 30 cm and each of the equal side is 12cm. find the area of the triangles.​

Answers

Answered by tharunhirithic
0

Answer:

9√15

Step-by-step explanation:

Area of triangle=√(s(s-a)(s-b)(s-c))

S=Half of perimeter=15cm

A,B and C are the three sides of a triangle.

a+b+c=30cm (Given)

A=B=12cm(Isosceles triangle)

Therefore,C=6cm

S-A=3cm=S-B

S-C=9cm

Area=√(15*3*3*9)

       =9√15

Answered by Vishal101100
0

here is your answer mate....

Given the triangle is isosceles therefore the third side will be = perimeter - 2×equal sides = 30 -24=6

therefore..... by using formula....

 \sqrt{s - (s - a} )(s - b)(s - c)

S = perimeter /2 = 30/2= 15

and a,b and c are sides...

putting values...

we get(sq 1215)answer

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