Question

an iscoseles right triangle has area 8cm square the length of its hypotenuse is​

Answer 1

$\huge \bold\red{answer}$

Given, area of an isosceles right triangle = 8 cm2

Area of an isosceles triangle = 1/2 (Base x Height)

⇒ 8 = 1/2 (Base x Base)

[∴ base = height, as triangle is an isosceles triangle]

⇒ (Base)2 =16

⇒ Base= 4 cm

In ΔABC, using Pythagoras theoremAC2 = AB2 + BC2 = 42 + 42 = 16 + 16⇒ AC2 = 32 ⇒ AC = √32 cm

[taking positive square root because length is always positive]Hence, the length of its hypotenuse is √32 cm.

$\huge \bold \red{follow \: me}$

Answer 2

Answer:

√32

Step-by-step explanation:

area of triangle =8 cm^2

1/2 (base * height) = 8

1/2 (base * base) = 8 (height = base)

base^2 = 16

using Pythagoras

base^2 + height^2 = hypotenuse^2

4^2 +4^2 = hypotenuse^2

16+16

√32=hypotenuse