An isoaceles triangle is such that each of the base angles is twice the vertical angle. Find the angles of the triangle.
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Let the triangle be ∆PQR
Let the vertical angle be y.
Then both the base angles will be 2y respectively.
Sum of the three angles of a triangle is 180°
Therefore,
y+2y+2y = 180°
or 5y = 180°
or y = 180°/5
or y = 36°
Hence, the three angles are -
Vertical angle (y) = 36°
Base angles (2y) = 36°×2 = 72°
Let the vertical angle be y.
Then both the base angles will be 2y respectively.
Sum of the three angles of a triangle is 180°
Therefore,
y+2y+2y = 180°
or 5y = 180°
or y = 180°/5
or y = 36°
Hence, the three angles are -
Vertical angle (y) = 36°
Base angles (2y) = 36°×2 = 72°
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