an isoceles right traingle has an area of 14 cm. fine the length of its base?
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so let the sides be x
ab=bc ac is the hypotenuse
ab=bc=x
area of triangle is half *base*height
so half*x*x=14
x^2=28
x=√28cm
ab=bc ac is the hypotenuse
ab=bc=x
area of triangle is half *base*height
so half*x*x=14
x^2=28
x=√28cm
pralaksha:
thnx
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