Question

An isoceles triangle with base 48cm has area 240cm square find the remaining sides

Answer 1

Answer:

Step-by-step explanation:

base=48cm

area=240cm²

By heron's formula we know that ,

area=√s(s-a)(s-b)(s-c)

here s=half of perimeter

a,b and c are the sides where a and b are the equal sides

let a and b =x

s=a+b+c/2

 =x+x+48/2

 = 2x+48/2

 =2(x+24)/2

 =x+24

area=√s(s-a)(s-b)(s-c)

240=√(x+24)((x+24)-x)((x+24)-x)((x-24)-48)

240=√(x+24)(x+24-x)(x+24-x)(x+24-48)

240=√(x+24)*24*24*(x-24)

240=24√(x+24)(x-24)

240/24=√(x)²-(24)²

10=√(x)²-(24)²

(10)²=x²-576

100=x²-576

x²=100+576

x²=676

x=26

so the other sides are 26cm