an isolated electron experiences a force of 8×10^-14 N towards east in an electric field then the electric field acting on the electron is
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Weight of 1 e − =mg
=9×10 −31 ×10
=9×10 −30
We know force F=Eq
⇒Eq=9×10 −30
⇒E= 1⋅6×10 −19
9×10 −30
⇒E=5⋅62×10
−11 N/C.
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The given the magnitude of the electric field in which an electron experiences an electric force 8×10^-14 N is equal to its weight.
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