an isosacles right triangle has two equal side of length 5 cm what is its area
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We know that the isosceles right triangle has two equal sides and a 90 degree angle between them. And we know that each side is equal to 5. so we will find the hypotenuse side by the Pythagorean Theorem.
Hint: Draw a picture will be better to see.
Pythagorean theorem: h^2 = a^2 + b^2 = 5^2 + 5^2 = 25 + 25 = 50 so h = sqrt(50) or h = 5sqrt(2)
Hope it helps:)
Hint: Draw a picture will be better to see.
Pythagorean theorem: h^2 = a^2 + b^2 = 5^2 + 5^2 = 25 + 25 = 50 so h = sqrt(50) or h = 5sqrt(2)
Hope it helps:)
aditya6575:
very bad
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Answer:
area of the isosceles right triangle is 12.5 cm ².
Step-by-step explanation:
Given that:
∠ABC = 90°
AB=BC = 5 cm
To find:
Area of isosceles right triangle
So, as we know that:
Area of isosceles right triangle = 1/2 × base×height
= 1/2 × BC × AB
= 1/2 × 5 × 5
= 25/2 cm ²
= 12.5 cm ²
Hence, the area of the isosceles right triangle is 12.5 cm ².
i hope it helps you
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