Question

an isoscale right angle has area 8 cm square the length of is hypotenuse is. a. √32.cm b.√16cm c.√48cm d.√24cm​

Answer 1

Answer:$\sqrt 32$

Step-by-step explanation:

given: area = $8cm^{2}$

area of triangle = $\frac{1}{2}$ x base x height

as its a isosceles triangle base=height

8 = base x height/2

16 = base x base

$base^{2}$ = 16

base = 4cm

now: $AC^{2}$ = $AB^{2} + BC^{2}$

$AC^{2}$ = 32

AC = ±$\sqrt{32}$ cm

we always take dimension in positive

so hypotenuse = √32

Answer 2

A. √32 cm

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