an isoscale triangle had perimeter 30 cm and each equal side is 12 cm find the area of triangle
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Answer:
Given ,
perimeter = 30 cm
length of each equal side = 12 cm
length of unequal side = 30 - 2( 12)
= 30 - 24 = 6 cm
Now to find the height , we draw the altitude from angle A as shown in the attachment.
The altitude makes a 90° with BC which means it perpendicularly bisects BC.
Lets take the point where the altitude meets BC as D .
DC = DB = 3 cm
Length of AD = ?
AD = √12² - 3²
= √144 - 9
= √135
= 11.618 cm [ approx. ]
area of triangle = 1/2 bh
b = 6 cm
h = 11.618
area = 1/2 × 6 × 11.618
= 34.854 cm²
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