Question

An isosceles∆ gas perimeter 30cnand each of equal sides is 12cm.Find the area of triangle


{NOTE:-Solve this by using"Heron's Formula"}


_/|\_Use Heron's formula

​

Answer 1

Answer:

Perimeter of isosceles triangle=30cm

Length of equal sides=12cm

Let third side of triangle=xcm

According to problem,

x+12+12=30

x+24=30

x=30−24

x=6

∴ Third side of triangle=6cm

Using Heron's formula

Area of triangle=

s(s−a)(s−b)(s−c)

sq. units

where s=

2

a+b+c

s=

2

30

=15

Area of triangle=

15(15−12)(15−12)(15−6)

cm

2

=

15×3×3×9

cm

2

=3×3×

15

cm

2

=9

15

cm

2

∴ Area of triangle=9

15

cm

2

Answer 2

Question ⤵

An isosceles∆ gas perimeter 30cnand each of equal sides is 12cm. Find the area of triangle .

Answer ⬇

Kindly see attachment..Sry for previous one..I solved it simple.

#pgli.

Thanks..