an isosceles right angle triangle has area 8 cm square the length of the hypotenuse is
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Step-by-step explanation:
According to the question:)-
Both the perpendicular and base are equal in length.
So Area of triangle = 1/2 x base X height
Let base = height = y
1/2 *y * y = 8
y² = √16
y = 4 cm
So length of Perpendicular = Base = 4cm
Now by the Pythagoras theorem we found:)-
4² + 4² = √ 16+ √16 = √32 = 4√2 cm
So required hypotenuse = 4√2 cm>
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Answer:
here are of a right angled triangle is 1/2×base×height=6
base × height=16
In an isosceles right angled triangle base and height are same
base × base =16
base =4
hypotenuse is equal to the square of base plus square of height
square root of 4 square plus 4 square
=4×square root of 2
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