Math, asked by lion0825, 1 year ago

an isosceles right angle triangle has area 8 cm square the length of the hypotenuse is​

Answers

Answered by Anonymous
11

Step-by-step explanation:

According to the question:)-

Both the perpendicular and base are equal in length.

So Area of triangle = 1/2 x base X height

Let base = height = y

1/2 *y * y = 8

y² = √16

y = 4 cm

So length of Perpendicular = Base = 4cm

Now by the Pythagoras theorem we found:)-

4² + 4² = √ 16+ √16 = √32 = 4√2 cm

So required hypotenuse = 4√2 cm>

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Answered by vishnuvardhan232
2

Answer:

here are of a right angled triangle is 1/2×base×height=6

base × height=16

In an isosceles right angled triangle base and height are same

base × base =16

base =4

hypotenuse is equal to the square of base plus square of height

square root of 4 square plus 4 square

=4×square root of 2

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