Question

an isosceles right angled current carrying loop pqrs is placed in a uniform magnetic field b pointing along PR if the magnetic force acting on the arm pq is f then the magnetic force which acts on the arm QR will be

Answer 1

Answer:

Force on arm PQ and arm QR is same i.e. equla to "f"

Explanation:

Let the side length of PQ is "L"

now the magnetic force on this side is given as

$F = i L B sin90$

$F = iLB$

now the side length of QR is given as

$QR = \sqrt2 L$

now its angle with the magnetic field is given as 45 degree

so we will have

$F = i(\sqrt2 L)B sin45$

$F = i L B$

so the force will be same as that on arm PQ

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Topic : Magnetic force

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