An isosceles right triangle has area 8 cm². The length of its hypotenuse is _____.
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Answer:
AREA OF RIGHT ANGLED TRIANGLE=A^2/4
8=A^2/4
A^2=32
A=√32
IN TRIANGLE ABC,
BASE=√32CM, HEIGHT=√32CM AND HYPOTENUSE=?
(AC)^2=(AB) ^2+(BC) ^2
AC^2=(√32) ^2 +(√32) ^2
AC=√32+32=√64
AC=8 CM
LENGTH OF HYPOTENUSE=8CM
Answered by
1
Answer:
Hence, the length of its hypotenuse is √32 cm
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