Question

An isosceles right triangle has area 8cm2 . Then fine the length of it's Hypotenuse​

Answer 1

Step-by-step explanation:

Let height of triangle = h

As the triangle is isosceles,

Let base = height =h

According to the question, Area of triangle = 8cm

2

⟹

2

1

×Base×Height=8

⟹

2

1

×h×h=8

⟹h

2

=16

⟹h=4cm

Base = Height = 4cm

Since the triangle is right angled,

Hypotenuse

2

=Base

2

+Height

2

⟹Hypotenuse

2

=4

2

+4

2

⟹Hypotenuse

2

=32

⟹Hypotenuse=

32

Hence, Options A is the correct answer.

Answer 2

Let the equal sides (base and height) of the triangle be a cm.

We know that the area of the triangle =>

$\frac{1}{2} \times base \times height$

Since it is given that the area of the isosceles right triangle is .

Now,

$\frac{1}{2} \times a \times a \: = 8 \\ {a = 16 \\ \\ }^{2}$

$a = 4$

Find the length of the hypotenuse

Pythagoras's theorem states that:

$hypotenuse \: = \sqrt{base ^{2} \times height {}^{2} }$

Now, the hypotenuse will be,

$hypotenuse \: = \sqrt{ {4}^{2} \ + {4}^{2} } \\ hypotenuse = \sqrt{16 + 16} \\ hypotenuse \: = \sqrt{32}$

So the answer is that.

I'm really sorry for late answer V⁠●⁠ᴥ⁠●⁠V

and make me as brainlist