Question

An isosceles spherical triangle has side b = 54°28’ side a = 92.5° and side c = 54°28’. What is the measure of angle B​

Answer 1

Answer:

B=41°45’

Step-by-step explanation:

sin co-B = \tan=tan a/2 * \tantan co -C

\cos B = \tan a/2 * 1/\tan ccosB=tana/2∗1/tanc

\cos B = \tan 92°30’/2 * 1/\tan 54°28’cosB=tan92°30’/2∗1/tan54°28’

\therefore B = 41°45’∴B=41°45’

Answer 2

Step-by-step explanation:

Given:-

A body is moving with a speed of 20 m/s. When a certain force is applied, an acceleration of 4 m/s² is produced.

To find:-

Time taken to become velocity 80 m/s.

Equation Used:-

{\boxed{\bf{First\: Equation\:of\:Motion:v=u+at}}}

FirstEquationofMotion:v=u+at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration

t = Time taken

Solution:-

Using first equation of motion,

\sf :\implies\:v=u+at:⟹v=u+at

Here,

v = 80 m/s

u = 20 m/s

a = 4 m/s²

Putting values,

\sf :\implies\:80=20+4t:⟹80=20+4t

\sf :\implies\:4t=80-20:⟹4t=80−20

\sf :\implies\:4t=60:⟹4t=60

\sf :\implies\:t=\dfrac{60}{4}:⟹t=

4

60

\sf :\implies\:t=15\:sec:⟹t=15sec

Hence, It will take 15 sec to become velocity 80 m/s.

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Answer 3

Step-by-step explanation:

Given:-

A body is moving with a speed of 20 m/s. When a certain force is applied, an acceleration of 4 m/s² is produced.

To find:-

Time taken to become velocity 80 m/s.

Equation Used:-

{\boxed{\bf{First\: Equation\:of\:Motion:v=u+at}}}

FirstEquationofMotion:v=u+at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration

t = Time taken

Solution:-

Using first equation of motion,

\sf :\implies\:v=u+at:⟹v=u+at

Here,

v = 80 m/s

u = 20 m/s

a = 4 m/s²

Putting values,

\sf :\implies\:80=20+4t:⟹80=20+4t

\sf :\implies\:4t=80-20:⟹4t=80−20

\sf :\implies\:4t=60:⟹4t=60

\sf :\implies\:t=\dfrac{60}{4}:⟹t=

4

60

\sf :\implies\:t=15\:sec:⟹t=15sec

Hence, It will take 15 sec to become velocity 80 m/s.

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Answer 4

Step-by-step explanation:

Given:-

A body is moving with a speed of 20 m/s. When a certain force is applied, an acceleration of 4 m/s² is produced.

To find:-

Time taken to become velocity 80 m/s.

Equation Used:-

{\boxed{\bf{First\: Equation\:of\:Motion:v=u+at}}}

FirstEquationofMotion:v=u+at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration

t = Time taken

Solution:-

Using first equation of motion,

\sf :\implies\:v=u+at:⟹v=u+at

Here,

v = 80 m/s

u = 20 m/s

a = 4 m/s²

Putting values,

\sf :\implies\:80=20+4t:⟹80=20+4t

\sf :\implies\:4t=80-20:⟹4t=80−20

\sf :\implies\:4t=60:⟹4t=60

\sf :\implies\:t=\dfrac{60}{4}:⟹t=

4

60

\sf :\implies\:t=15\:sec:⟹t=15sec

Hence, It will take 15 sec to become velocity 80 m/s.

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