Question

An isosceles trapezium abcd in order with ab is equal to 6, cd is equal to 12 and area is equal to 36 square units find length of the side bc is

Answer 1

Answer:

BC=AD=5 units

Step-by-step explanation:

ar(ABCD)=1/2*(sum of parallel sides)*altitude

36 sq unit=1/2*(6+12)*altitude

altitude= 4 units

Now,

(non parallel side of an isosceles trapezium)^2=((bigger side -smaller parallel side)/2)^2+ altitude^2

BC^2=((12-6)/2)^2+4^2

BC^2=3^2+4^2

BC^2=9+16

BC=5 units