An isosceles triangle ABC has AB = AC = 20 cm. If the side BC is 16 cm and D is the midpoint of BC, calculate the length of AD.
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D is the midpoint of BC. So BD=BC = 8cm
According to Pythagoras theorem,
AB^2 = AD^2 + BD^2
400cm^2 = AD^2 + 64cm^2
AD^2 = (400-64) cm^2
= 336cm^2
AD=18.3 cm.
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