an isosceles triangle ABC HAVING SIDE AB=AC=17CM AND BC= 16CM FIND THE AREA OF TRINGLE ABC
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Answer:
90 cm²
Step-by-step explanation:
Draw a perpendicular line from point A.
Let the line AH.
We know that AH ⊥ BC.
According to ΔABH ≡ ΔACH, BH = CH = 8 cm.
Pythagorean Theorem : ΔABH is a right triangle with ∠H=90°.
AH² + BH² = AB²
AH² + 8² = 17²
AH = √(17² - 8²) = 15
BC is a base of ΔABC.
Thus, AH is height of ΔABC.
∴ ΔABC = (1/2) × 16 × 15 = 90 cm²
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