Question

an isosceles triangle ABC HAVING SIDE AB=AC=17CM AND BC= 16CM FIND THE AREA OF TRINGLE ABC

Answer 1

Answer:

90 cm²

Step-by-step explanation:

Draw a perpendicular line from point A.

Let the line AH.

We know that AH ⊥ BC.

According to ΔABH ≡ ΔACH, BH = CH = 8 cm.

Pythagorean Theorem : ΔABH is a right triangle with ∠H=90°.

AH² + BH² = AB²

AH² + 8² = 17²

AH = √(17² - 8²) = 15

BC is a base of ΔABC.

Thus, AH is height of ΔABC.

∴  ΔABC = (1/2) × 16 × 15 = 90 cm²