Question

An isosceles triangle has a base 6 cm long and one of the equal sides is 5 cm long. Find the area of the
triangal​

Answer 1

Answer:

$12$ ans

Step-by-step explanation:

let equal sides = a = 5

and base = b = 6

then area of isosceles triangle = $\frac{b\sqrt{a^{2}-\frac{b^{2} }{4} } }{2}$

put values into the formula

= $\frac{6\sqrt{5^{2}-\frac{6^{2} }{4} } }{2}$

= $\frac{6\sqrt{5^{2}- 9 } }{2}$

= $\frac{6\sqrt{25- 9 } }{2}$

= $\frac{6\sqrt{16 } }{2}$

= $\frac{6.4 }{2}$

= $12$ ans

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