An isosceles triangle has an area of 8cm.Fimd the length of its hypotenuse
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The formula for area of isosceles Triangle =1/2×b×h
as in figure we consider equal sides as x
area =1/2×x×x
8=1/2×2x
8=x
so x=8
Now ,
by Pythagoras theorem
hyp² = side1²+side2²
= 8²+8²
64+64
hyp²=128
taking square root
step by step
hypotenuse= √128
= √4×32 (simplifying)
=√4×4×8
=√4×4×4×2
=√4×4×2×2×2
taking out of √
= 4×2√2
= 8√2
hope it helps
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