Question

An isosceles triangle has angle A 30 degrees greater than angle B. Find all angles of the triangle.

Answer 1

Answer:

Let the base angles be

′

x

′

Therefore,

x+x+40

∘

=180

∘

[Given]

2x=180

∘

−40

∘

2x=140

∘

x=70

∘

Hence,

The base angles of the triangle are 70

∘

,70

∘

.

Answer 2

Answer:

If we assume

angle A=x+30

angle B and C=x

therefore x+x+x+30=180

therefore 3x+30=180

therefore x=50

A=80 B=C=50