Question

an isosceles triangle has base 6 and long and one of equal side is 5 cm long find the area of triangle
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Answer 1

$\huge\mathbb{\underline{QUESTION:-}}$

an isosceles triangle has base 6 and long and one of equal side is 5 cm long find the area of triangle

$\huge\mathbb{\underline{\purple{SOLUTION:-}}}$

$\large\sf{\red{Given:-}}$

It's an isosceles triangle in which two sides are equal

Two equal sides are 5 cm

and one side 6cm

Now According to question we have to find the area of triangle we can find this by heron's Formula

$\sf\large \sqrt{s(s-a)(s-b)(s-c)}$

where the value of s=$\sf\frac{a+b+c}{2}$

$\large\boxed{\sf{Solution}}$

a =5cm,

b=5cm

c=6cm

$\sf\large \sqrt{s(s-a)(s-b)(s-c)}$

s =$\sf \frac{5+5+6}{2}= \frac{\cancel16}{\cancel2}=8$

the value of s =8

Area=$\sf\longrightarrow \sqrt{8(8-5)(8-5)(8-6)}$

$\sf\longrightarrow Area = \sqrt{8×3×3×2}\\ \sf\longrightarrow Area= \sqrt{24×6}\\ \sf\longrightarrow Area = \sqrt{144}\\ \sf\longrightarrow Area\:of\: triangle=12cm{}^{2}$

$\sf\boxed{\underline{\red{AREA\:of\: triangle=12cm{}^{2}}}}$