An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.
Answers
Answered by
818
Let The Third Side Be xcm.
Now Perimeter = 12+12+x
24+x = 30
x = 6
Now Find The Area Using Herons Formula
Semiperimeter = 30/2 = 15
Sq Root(15(15-12)(15-12)(15-6) ) = Sq Root(15*3*3*9) = Sq Root(1215) = 34.85 cm^2
So Area is 34.85cm^2
Now Perimeter = 12+12+x
24+x = 30
x = 6
Now Find The Area Using Herons Formula
Semiperimeter = 30/2 = 15
Sq Root(15(15-12)(15-12)(15-6) ) = Sq Root(15*3*3*9) = Sq Root(1215) = 34.85 cm^2
So Area is 34.85cm^2
Answered by
994
SOLUTION
Length of the equal sides = 12cm
Perimeter of the triangle = 30cm
Length of the third side = 30 - (12+12) cm = 6cm
Semi perimeter of the triangle(s) = 30/2 cm = 15cm
Using heron's formula,
Area of the triangle = √s (s-a) (s-b) (s-c)
= √15(15 - 12) (15 - 12) (15 - 6)cm2
= √15 × 3 × 3 × 9 cm2
= 9√15 cm2
Length of the equal sides = 12cm
Perimeter of the triangle = 30cm
Length of the third side = 30 - (12+12) cm = 6cm
Semi perimeter of the triangle(s) = 30/2 cm = 15cm
Using heron's formula,
Area of the triangle = √s (s-a) (s-b) (s-c)
= √15(15 - 12) (15 - 12) (15 - 6)cm2
= √15 × 3 × 3 × 9 cm2
= 9√15 cm2
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