Math, asked by krishankewal5772, 8 months ago

An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the other two
sides and the area of the triangle.

Answers

Answered by mammachan76
0

Answer:

12+12+x=30

24+x=30

30-24=x

60=x

Hope it helps.

Answered by Anonymous
3

Given :

Perimeter =30 cm

Equal side =12 cm.

So, let the third side be x.

12+12+x=30

24+x=30

x=30-24

Area of triangle :

(By heron's formula)

x=6 cm

Find :

semi perimeter =30/2

=15

Area of triangle =

 \sqrt{s(s - a)(s-b)(s-c)} \\  = \sqrt{15(15 - 12)(15 - 12)(15 - 6)}  \\  =  3 \times   5 \times 3  \times  3 \times 3 \ \times 3 \\  = 3 \ \times  3 \sqrt{15}  \\  = 9 \sqrt{15} \: cm ^{2}  </h2><h2>   </h2><h2>

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