An isosceles triangle has perimeter 30 cm, and each of the equal side is 12 cm. Find the area of the triangle.
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Perimeter of isosceles triangle=30cm
Length of equal sides=12cm
Let third side of triangle=xcm
According to problem,
x+12+12=30
x+24=30
x=30−24
x=6
∴ Third side of triangle=6cm
Using Heron's formula
Area of triangle=
s(s−a)(s−b)(s−c)
sq. units
where s= 2a+b+c
s= 230=15
Area of triangle= 15(15−12)(15−12)(15−6)cm 2
= 15×3×3×9 cm 2
=3×3× 15 cm 2
=9 15 cm 2
∴ Area of triangle=9 15 cm 2 .
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First,let the third side be x.
It is given that the length of the equal sides us 12 cm and it's perimeter is 30 cm.
So,
So,the length of the third side is 6 cm.
Thus,the semi perimeter of the isosceles triangle (s) = 30/2 cm =15 cm
By using Heron's Formula,
Area of the triangle,
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